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Question 3. On Comparing the Ratios A1/a2 , B1/b2  and C1/c2 Find Exercise 3.2 Chapter 3 Pair of Linear Equations in

Question 3. On comparing the ratios a1/a2 , b1/b2  and c1/c2 find out whether the followin Chapter 3: Pair of Linear Equations in Two Variable Maths Class 10 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3. On comparing the ratios a1/a2 , b1/b2  and c1/c2 find out whether the following pair of linear equations are consistent, or inconsistent. (i) 3x + 2y = 5 ; 2x – 3y = 7 (ii) 2x – 3y = 8 ; 4x – 6y = 9 (iii) 3/2x + 5/3 y = 7 ; 9x – 10y = 14 (iv) 5x – 3y = 11 ; – 10x + 6y = –22 (v)4/3x + 2y =8  ; 2x + 3y = 12 (i) 3x + 2y = 5 ; 2x – 3y = 7 is solved by our expert teachers. You can get ncert solutions and notes for class 10 chapter 3 absolutely free. NCERT Solutions for class 10 Maths Chapter 3: Pair of Linear Equations in Two Variable is very essencial for getting good marks in CBSE Board examinations

Question 3. On comparing the ratios a1/a2 , b1/b2  and c1/c2 find out whether the following pair of linear equations are consistent, or inconsistent.
(i) 3x + 2y = 5 ; 2x – 3y = 7
(ii) 2x – 3y = 8 ; 4x – 6y = 9
(iii) 3/2x + 5/3 y = 7 ; 9x – 10y = 14
(iv) 5x – 3y = 11 ; – 10x + 6y = –22
(v)4/3x + 2y =8  ; 2x + 3y = 12
(i) 3x + 2y = 5 ; 2x – 3y = 7
Solution:
Convert the equation in form of  a1x + b1y + c1 = 0  and a2x+ b2y + c2 = 0
We get
3x + 2y - 5 =0  and  2x – 3y – 7  =0
Compare the equation with

We get
a1 = 3,            b1       = 2,                 and c1 = -5
a2 =2              b2        =-3                  and c2 = -7

We get

Hence both lines are Consistent
(ii) 2x – 3y = 8 ; 4x – 6y = 9
Convert the equation in form of  a1x + b1y + c1 = 0  and a2x+ b2y + c2 = 0
We get
2 x – 3 y - 8 = 0  and  4x – 6 y – 9  =0
Compare the equation with

We get
a1 = 2,            b1       = -3,               and c1 = - 8
a2 = 4             b2        = - 6                and c2 = - 9

So we get

So both lines are Inconsistent
(iii)        3/2x + 5/3 y = 7 ; 9x – 10y = 14
Convert the equation in form of a1x + b1y + c1 = 0  and a2x+ b2y + c2 = 0
We get
3/2 x  + 5/3 y - 7 = 0  and  9x – 10 y - 14  =0
Compare the equation with

We get
a1 = 3/2,         b1       = 5/3,             and c1 = - 7
a2 = 9             b2        = - 10              and c2 = - 14

So we get

So both lines are Consistent
(iv)        5x – 3y = 11 ; – 10x + 6y = –22
Convert the equation in form of a1x + b1y + c1 = 0  and a2x+ b2y + c2 = 0
We get
5 x  -3 y - 11 = 0  and  -10 x + 6 y + 22 =0
Compare the equation with

We get
a1 = 5             b1        = - 3,              and c1 = - 11
a2 = -10          b2        =  6                  and c2 =   22

So we get

Hence
So both lines are dependent and consistent  
(v)4/3x + 2y =8  ; 2x + 3y = 12
Convert the equation in form of a1x + b1y + c1 = 0  and a2x+ b2y + c2 = 0
We get
4/3 x  + 2 y - 8 = 0  and  2x + 3 y - 12  =0
Compare the equation with

We get
a1 = 4/3,         b1       = 2,                 and c1 = -8
a2 = 2             b2        = 3                   and c2 = - 12

So we get

So both lines are Dependent and consistent

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